# The greatest height to which a man can throw a ball is h.What is the greatest distance to which he can throw the ball?

$\begin{array}{1 1}\large\frac{h}{4}\\\large\frac{h}{2}\\h\\2h\end{array}$

Answer : $2h$
$v=\sqrt{2gh}$
Greatest distance =$\large\frac{v^2}{g}=\frac{2gh}{g}$
$\Rightarrow 2h$