$\begin{array}{1 1}160km/hr\\180km/hr\\260km/hr\\280km/hr\end{array} $

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Answer : 160km/hr

Let us first identify the car and train as A and B. Here, we are provided with the speed of car (A) with respect to Earth i.e. and speed of train (B) with respect to A i.e

$v_A=80km/hr$

$v_{BA}=80\sqrt 3$km/hr

We are required to find the speed of train (“B”) with respect to Earth i.e. , . From equation of relative motion, we have :

$\Rightarrow v_B=\sqrt{\big(v_{BA}^2+v_A^2\big)}$

$\Rightarrow \sqrt{\{(80\sqrt 3)^2+80^2}\}$=160km/hr

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