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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
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A car is moving at a speed $50 \;km /h$ two seconds there it is moving at $60 \;km/h$ Calculate the acceleration of the car.

$\begin{array}{1 1} 2.39 \;m/s^2 \\ 1.39\;m/s^2 \\ 3.45\;m/s^2 \\1.98\;m/s^2\end{array} $

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Answer : $ 1.39\;m/s^2$
Here, $v_0 = 50 \;km/h =50 \times \large\frac{5}{18}$$m/s$
$\qquad= \large\frac{250}{18} $$m/s$ and
Since $a= \large\frac{v-v_0}{t}$
$\qquad= \large\frac {\Large\frac{300}{18}-\frac{250}{18}} {2}$
$\qquad= \large\frac{\Large\frac{50}{18}}{2}$
$\qquad= \large\frac{50}{36}$$=1.39 \;m/s^2$
answered Aug 13, 2014 by meena.p

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