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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Plane

A typical carnival ferris wheel has a radius of 9.0m and rotates 4.0 times per minute.What magnitude acceleration do the riders experience?

$\begin{array}{1 1}1.6m/s^2\\2.6m/s^2\\3.6m/s^2\\4.6m/s^2\end{array} $

1 Answer

Answer : $1.6m/s^2$
The period is $T=\large\frac{1}{4}$ min=15s
A rider's speed is $v=\large\frac{2\pi r}{T}$
$\Rightarrow \large\frac{2\pi (9.0m)}{15s}$
$\Rightarrow 3.77m/s$
Consequently,the centripetal acceleration is
$a=\large\frac{v^2}{r}$
$\Rightarrow \large\frac{(3.77m/s)^2}{9.0m)}$
$\Rightarrow 1.6m/s^2$
answered Aug 14, 2014 by sreemathi.v
 

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