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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Plane
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A stereo turntable has a frequency of 33 revolutions per minute.A record of radius 15.25 centimeters is placed on the turnable and begins to rotate.The velocity of a point on the edge of the record is

$\begin{array}{1 1}2.16m/s\\22.23m/s\\0.53m/s\\7.62m/s\end{array} $

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Answer : 0.53m/s
First we convert 33 rpm into radians per second.We note that there are $2\pi$ rad/rev and 60s in 1 min.The conversion gives an angular frequency of $3.454rad/s$.Now we convert the radius to meters so that we are in SI units(MKS).Thus,R=0.1525m.Now we know that,for uniform circular motion,$v=R\omega$,so
$v=(0.1525m)(3.454rad/s)=0.53m/s$
answered Aug 14, 2014 by sreemathi.v
 

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