Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
0 votes

A stone is allowed to fall from the top of tower 100 metre high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25\;ms^{-1} $. The two stones will meets after

$\begin{array}{1 1} 4\;s \\ 0.4\;s \\ 0.04\;s \\.40\;s \end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : 4s
$x= \large\frac{1}{2}$$gt^2,100-x=25t - \large\frac{1}{2}$$gt^2$
Adding $25 t= 100$ or $t= 4s$
answered Aug 19, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App