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# A stone is allowed to fall from the top of tower 100 metre high and at the same time another stone is projected vertically upwards from the ground with a velocity of $25\;ms^{-1}$. The two stones will meets after

$\begin{array}{1 1} 4\;s \\ 0.4\;s \\ 0.04\;s \\.40\;s \end{array}$

$x= \large\frac{1}{2}$$gt^2,100-x=25t - \large\frac{1}{2}$$gt^2$
Adding $25 t= 100$ or $t= 4s$