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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Motion in a Straight Line
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An electron starting from rest has a velocity that increases linearly with time i.e $v= kt$ where $k=2\;m\;s^{-2}$. The distance covered in the first 3 second is

$\begin{array}{1 1} 9\;m \\ 16\;m \\ 27\;m \\ 36\;m \end{array} $

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1 Answer

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Answer : 9 m
$dS=kt dt$
$S=\large\frac{1}{2}$$kt^2$
$\quad= \large\frac{1}{2}$$ \times 2 \times 3 \times 3\;m=9\;m$
$\qquad= 9\;m$
answered Aug 19, 2014 by meena.p
 

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