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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Motion in a Straight Line

A body moving in a straight line covers a distance of $14 m $ in the 5th second and 20 m in the 8th second. How much distance will it cover in the 15th second ?

$\begin{array}{1 1} zero \\ 34\;m \\ 4\;m \\2\;m \end{array} $

1 Answer

$S_N = u+\large\frac{a}{2} $$(2n-1)$
$S_5= u+ \large\frac{9a}{2}$-------(1)
$S_8= u+ \large\frac{15a}{2}$-------(2)
Solving (1) and (2) we get $a-2 \;ms^{-2}$ and $ u-5\;ms^{-1}$
$S_{15}=u + \large\frac{29a}{2} $
$\quad= 5 +\large\frac{29 \times 2}{2}$$=34\;m$
answered Aug 19, 2014 by meena.p
The value of a and  u in above solution won't be negative.
 

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