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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
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If a net horizontal force of 130 N is applied to a person with mass 60 kg who is resting on the edge of a swimming pool, what is the horizontal acceleration produced?

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Answer: 2.2 ms$^{-2}$
According to Newton's second law, $\large\Sigma$$F = 130 N = ma = 60 \times a \rightarrow a = \large\frac{130}{60}$$ = 2.2\; m/s^2$
answered Aug 19, 2014 by balaji.thirumalai
 

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