Answer: 216 m

Let us set up the problem first:

Given $F, m$ we first need to calculate $a_x$.

From Newton's 2nd law, $F = 140 N = ma_x = 32.5 \times a_x \rightarrow a_x = \large\frac{140}{32.5}$$ = 4.31\;m/s^2$

Given that we have $a_x$, we can now calculate the distance traveled from the kinematics equation: $x = x_0 + V_0t + \large\frac{1}{2}$$a_xt^2$

$\Rightarrow x = 0+ 0 \times 10.05 + \large\frac{1}{2}$$ 4.31 \times 10.05^2 = 216\;m$