Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A cyclist has to lean inwards when negotiating a curved unbanked road. The cyclist leans with an angle $\theta$ to the vertical. $N$ is the normal reaction given by $N=mg$, where $m$ is the mass of the cyclist and the bicycle combined. The radius of the curved road is $R$. The force of friction is given by $F=\mu N$ where $\mu$ is the co-efficient of friction. Assuming the cyclist skids which of the following is true?

$v \gt \sqrt {\mu g R}, \quad v \lt \sqrt {\mu g R},\quad$$v = \sqrt {\mu m g R},$$\quad v \gt \sqrt {\mu m g R}$
Can you answer this question?

1 Answer

0 votes
The problem can be represented as follows:
$F = \mu N = \mu m g$.
The cyclist will skid if the centripetal force $\large\frac{mv^2}{R}$ exceeds the frictional force $F = \mu m g$.
$\Rightarrow$ the cyclist skids if $v \gt \sqrt{\mu g R}$
answered Aug 25, 2014 by balaji.thirumalai

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App