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A car of mass $750\;kg$ moves around a circular track of radius $50\;m$ with a speed of $10\;ms^{-1}$. What's the centripetal force on the car?

$\begin{array}{1 1} 21.7\;N \\ 1500\;N \\ 2.79\;N \\3.64\;N \end{array} $

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Answer : $ 1500\;N$
By Newton's second law the force F producing this acceleration on a massm towards the center of rotation is
$F= ma = \large\frac{mv^2}{r}$
$F= \large\frac{mv^2}{r} =\frac{750 \times 10^2}{50}$
$\qquad= 1500\;N$
answered Aug 25, 2014 by meena.p

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