$\begin{array}{1 1} 10\; m \\ 13\;m \\ 14\;m \\ 16 \;m \end{array} $

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Answer : $10\; m$

Speed of car $(v) =36 \;km\;h^{-1} =10 ms^{-1}$

The maximum centripetal force that friction can provide is

$f_{max} =\mu \;mg =\large\frac{mv^2}{R}$

$R_{min} =\large\frac{v^2}{\mu g}= \frac{10 \times 10}{0.8 \times 10}$

$\qquad= 12.5\;m$

This is the minimum radius the curve must have for the car to negotiate it with out sliding at a speed of $10 \;ms^{-1}.$

Hence the correct choice is (a)

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