$\begin{array}{1 1} 10\; m \\ 13\;m \\ 14\;m \\ 16 \;m \end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Answer : $10\; m$

Speed of car $(v) =36 \;km\;h^{-1} =10 ms^{-1}$

The maximum centripetal force that friction can provide is

$f_{max} =\mu \;mg =\large\frac{mv^2}{R}$

$R_{min} =\large\frac{v^2}{\mu g}= \frac{10 \times 10}{0.8 \times 10}$

$\qquad= 12.5\;m$

This is the minimum radius the curve must have for the car to negotiate it with out sliding at a speed of $10 \;ms^{-1}.$

Hence the correct choice is (a)

Ask Question

Take Test

x

JEE MAIN, CBSE, AIPMT Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...