$\begin{array}{1 1} 7.5\; cm \\ 10\;cm \\ 12.5\;cm \\ 15 \;cm \end{array} $

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Speed of train $(v) =36\;km\;h^{-1}=10\;ms^{-1}$

Radius of the curve $(R) =200\;m$

Distance between rails $(x)=1.5 \;m$

Let the outer rails be raised by a height h with respect to the inner rails so that the angle of banking is $\theta$

Then $\tan \theta= \large\frac{h}{x}=\frac{v^2}{Rg}$

or $h= \large\frac{xv^2}{Rv}$

or $ \qquad= 0.075\;m$

$\qquad= 7.5\;cm$

Answer: $ 7.5\; cm$

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