Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A train rounds an unbanked circular bend of radius 50 m at a speed of $54\;km\;h^{-1}$. If $g= 10 \;m/s^{-2}$, the angle of banking required to prevent wearing out of rails is given by

$\begin{array}{1 1} \theta= \tan^{-1}(0.15) \\ \theta=\tan^{-1}(0.25) \\ \theta= \tan^{-1} (0.35) \\ \theta= \tan^{-1}(0.45) \end{array} $

Can you answer this question?

1 Answer

0 votes
Now $v= 54\;km\;h^{-1}=15 ms^{-1}$
$R= 50\;m$
The required angle of banking is given by
$ \tan \theta = \large\frac{v^2}{Rg}$
$\qquad= \large\frac{15 \times 15}{50 \times 10}$
$\qquad= 0.45$
answered Aug 26, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App