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# Consider a block sliding down a frictionless inclined plane with acceleration a . If we double the mass of the block,what is its acceleration?

$\begin{array}{1 1}\large\frac{a}{4}\\\large\frac{a}{2}\\a\\2a\end{array}$

• All problems in laws-of-motion that concern a frictionless inclined plane can be represented by the diagram below, where N = normal force that is perpendicular to the plane, m = mass of object, g = acceleration due to gravity, $\theta$ (theta) = angle of elevation of the plane, measured from the horizontal
• Component of gravity pushing the block down the incline plane = $mg \sin \theta$
• Component of gravity pushing the block against the incline plane = $mg \cos \theta$
$F = ma = mg\sin \theta$
$a =g\sin \theta$