Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Laws of Motion
0 votes

A crate of mass m = 100kg is pushed at constant speed up a frictionless ramp $\theta=30^{\large\circ}$ by a horizontal force $\overrightarrow{F}$.What are the magnitudes of $\overrightarrow{F}$ and the force of the crate from the ramp?

$\begin{array}{1 1}556N,F_N=1.13\times 10^3N\\278N,F_N=1.13\times 10^4N\\446N,F_N=1.13\times 10^3N\\556N,F_N=1.13\times 10^4N\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : $556N,F_N=1.13\times 10^3N$
Free body diagram :
We resolve this horizontal force into appropriate components
Newton's second law applied to the x-axis produces
For $a=0$,this yields $F=566$N
Applying Newton's second law to the y axis (where there is no acceleration),we have
$F_N-F\sin \theta-mg\cos \theta = 0$
Which yields the normal force $F_N=1.13\times 10^3N$
answered Aug 27, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App