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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Work, Power and Energy

How much work is done when a constant force of 500 N is used to push a cart through a displacement of magnitude 25 m to final position along the $x$-axis

$\begin{array}{1 1}12500\;J\\12000\;J\\11500\;J\\13500\;J\end{array} $

1 Answer

Answer : 12500 J
Amount of Work is $W = F ⋅ d$
$\qquad\qquad\qquad\qquad$=500 N.25 m
$\qquad\qquad\qquad\qquad$=12500 Nm
$\qquad\qquad\qquad\qquad=12500$ J
answered Aug 28, 2014 by sreemathi.v
edited Sep 2, 2014 by sreemathi.v
 

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