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Work, Power and Energy
A particle moves under the effect of a force $F=Cx$ from $x=0$ to $x=x_1$.The work done in the process is
$\begin{array}{1 1}Cx_1^2\\\large\frac{1}{2}\normalsize Cx_1^2\\Cx_1\\\text{Zero}\end{array} $
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Aug 28, 2014
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sreemathi.v
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Sep 1, 2014
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1 Answer
Answer : $\large\frac{1}{2}$$ Cx_1^2$
Work done = $\int\limits_{x_1}^{x_2} Fdx $
$\qquad\qquad=\int\limits_{0}^{x_1} Cxdx$
$\qquad\qquad=C\big[\large\frac{x^2}{2}\big]_{0}^{x_1} $
$\qquad\qquad=\large\frac{1}{2}$$ Cx_1^2$
answered
Aug 28, 2014
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sreemathi.v
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Sep 2, 2014
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