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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Work, Power and Energy

A particle is moved along the $x$-axis by a force which measures $\large\frac{10}{(1+x)^2}$ at a point $x$ feet from the origin.Find the work done (in ft-lb) in moving a particle from the origin to a distance of 9ft.

$\begin{array}{1 1}9ft-lb\\8ft-lb\\12ft-lb\\5ft-lb\end{array} $

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1 Answer

Answer : 9ft-lb
W=$\int\limits_0^9\large\frac{10}{(1+x)^2}$$dx$
$\;\;\;=-\large\frac{10}{1+x}\bigg|_0^9$
$\;\;\;=-1-(-10)$
$\;\;\;=9$ft-lb
answered Aug 28, 2014 by sreemathi.v
 

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