Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

Work done in time t on a body of mass $m$ which is accelerated from rest to a speed $v$ in time $t_1$ as a function of time $t$ is given by

$\begin{array}{1 1}\large\frac{1}{2}\normalsize m\large\frac{v}{t_1}\normalsize t^2\\ m\large\frac{v}{t_1}\normalsize t^2\\\large\frac{1}{2}\big(\frac{mv}{t_1}\big)^2\normalsize t^2\\\large\frac{1}{2}\normalsize m\large\frac{v^2}{t_1^2}\normalsize t^2\end{array} $

Can you answer this question?

1 Answer

0 votes
Answer : $\large\frac{1}{2}\normalsize m\large\frac{v^2}{t_1^2}\normalsize t^2$
Work done =$F.s=ma\big(\large\frac{1}{2}$$at^2\big)$
$\qquad\qquad\qquad =\large\frac{1}{2}$$ma^2t^2$
As acceleration $(a)=\large\frac{v}{t_1}$
$\qquad\qquad\qquad= \large\frac{1}{2}\normalsize m\large\frac{v^2}{t_1^2}\normalsize t^2$
answered Sep 1, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App