logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Work, Power and Energy
0 votes

Work done in time t on a body of mass $m$ which is accelerated from rest to a speed $v$ in time $t_1$ as a function of time $t$ is given by

$\begin{array}{1 1}\large\frac{1}{2}\normalsize m\large\frac{v}{t_1}\normalsize t^2\\ m\large\frac{v}{t_1}\normalsize t^2\\\large\frac{1}{2}\big(\frac{mv}{t_1}\big)^2\normalsize t^2\\\large\frac{1}{2}\normalsize m\large\frac{v^2}{t_1^2}\normalsize t^2\end{array} $

Can you answer this question?
 
 

1 Answer

0 votes
Answer : $\large\frac{1}{2}\normalsize m\large\frac{v^2}{t_1^2}\normalsize t^2$
Work done =$F.s=ma\big(\large\frac{1}{2}$$at^2\big)$
$\qquad\qquad\qquad =\large\frac{1}{2}$$ma^2t^2$
As acceleration $(a)=\large\frac{v}{t_1}$
$\qquad\qquad\qquad= \large\frac{1}{2}\normalsize m\large\frac{v^2}{t_1^2}\normalsize t^2$
answered Sep 1, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...