$\begin{array}{1 1}\large\frac{\pi}{4}\\\large\frac{\pi}{2}\\\large\frac{\pi}{2}\\\pi\end{array} $

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Answer : $\large\frac{\pi}{4}$

The displacement variable is $x$ (not s) we can use the formula $dW = Fdx=\large\frac{dx}{1+x^2}$.Then

$W=\int dW$

$\;\;\;\;=\int\limits_0^{1} \large\frac{dx}{1+x^2}$

$\;\;\;\;=\int\limits_0^{\Large\frac{\pi}{4}} \large\frac{\sec^2\theta}{1+\tan^2\theta}$$d\theta$

$\;\;\;\;=\int\limits_0^{\Large\frac{\pi}{4}} d\theta$

$\;\;\;\;=\large\frac{\pi}{4}$

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