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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Work, Power and Energy

Force $F=(3x^2N)i+(4N)j$ acts on a particle changing only the kinetic energy of the particle.How much work is done on the particle as it moves from coordinates (2m,3m) to (3m,0m)?

$\begin{array}{1 1}7.0J\\8.0J\\6.0J\\5.0J\end{array} $

1 Answer

Answer : 7.0J
$W=\int\limits_2^3 3x^2dx+\int\limits_3^0 4dy$
$\;\;\;\;=3\int\limits_2^3 x^2dx+4\int\limits_3^0 dy$
$\;\;\;\;=3[\large\frac{1}{3x^3}]$$\big|_2^3+4[y]\big|_3^0$
$\;\;\;\;=[3^3-2^3]+4[0-3]$
$\;\;\;\;=7.0J$
answered Sep 1, 2014 by sreemathi.v
 

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