# Find the work done by F as it moves from a to b.

$\begin{array}{1 1}625J\\224J\\650J\\525J\end{array}$

$W=\int\limits_a^b\overrightarrow{F}. \overrightarrow{ds}$
$\;\;\;\;=\int\limits_0^{10\cos 30} 30xdx+\int\limits_0^{10 \sin 30} 40y \cos 180 dy$
$\;\;\;\;=\large\frac{30x^2}{2}\big]_0^{8.66}-\large\frac{40y^2}{2}\big]_0^5$
$\;\;\;\;=1125-500$
$\;\;\;=625J$

answered Sep 1, 2014
edited Sep 2, 2014