$\begin{array}{1 1}301N/m\\300N/m\\201N/m\\200N/m\end{array} $

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Answer : 301N/m

$-N+kx-mg\sin 15^{\large\circ}+\mu_s N-mg\cos 15^{\large\circ}=0$

$N=\large\frac{mg\cos 15^{\Large\circ}}{\mu_s}$

$kx =mg\sin 15^{\large\circ}+\large\frac{mg\cos 15^{\Large\circ}}{\mu_s}=$$mg\big(\sin 15^{\large\circ}+\large\frac{\cos 15^{\large\circ}}{\mu_s}\big)$

$k=\large\frac{mg}{x}$$\big(\sin 15^{\large\circ}+\large\frac{\cos 15^{\large\circ}}{\mu_s}\big)$

$\;\;\;=\large\frac{(2kg)(9.8m/s^2)}{0.12m}$$\big(\sin 15^{\large\circ}+\large\frac{\cos 15^{\Large\circ}}{0.61}\big)$

$\;\;\;=301N/m$

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