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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Q)

Find the equation of a circle concentric with the circle $x^2+y^2-6x+12y+15=0$ and has double of its area.

[Hint:concentric circles have the same centre.]

$\begin{array}{1 1}x^2+y^2-6x+12y-30=0\\x^2+y^2-6x+12y+30=0\\x^2+y^2-6x+12y-15=0\\x^2+y^2-6x+12y-45=0\end{array} $

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