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# State whether the following statement is True or False: If the line $lx+my=1$ is a tangent to the circle $x^2+y^2=a^2$,then the point $(l,m)$ lies on a circle.

[Hint: Use that distance from the centre of the circle to the given line is equal to radius of the circle.]

$\begin{array}{1 1}\text{True}\\\text{False}\end{array}$

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A)
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• If a line $y=mx+c$ is a tangent to a circle,then the distance from the centre of the circle to the given line is equal to radius of the circle.
The equation of the given circle is $x^2+y^2=a^2$.
Hence its centre lies on the origin $O(0,0)$
Hence the perpendicular distance of the given line $lx+my-1=0$ is the radius.
$\therefore r=\bigg|\large\frac{l(0)+m(0)-1}{\sqrt{l^2+m^2}}\bigg|=\frac{1}{\sqrt{l^2+m^2}}$-----(1)
Condition for a line $y=mx+c$ to be a tangent to a circle is $r=\large\frac{c}{\sqrt{m^2+1}}$
Where $c$ is the intercept and $m$ is the slope of the line.
Here in the line $lx+my-1$;slope $m=-\large\frac{l}{m}$
$c=\large\frac{1}{m}$
$\therefore r=\large\frac{\Large\frac{1}{m}}{\sqrt{(-\Large\frac{l}{m})^2+1}}=\frac{1}{\sqrt{l^2+m^2}}$------(2)