Email
Chat with tutor
logo

Ask Questions, Get Answers

X
 
Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
Answer
Comment
Share
Q)

If $e$ is the eccentricity of the ellipse $\large\frac{x^2}{a^2}+\frac{y^2}{b^2}\normalsize =1\;(a < b)$,then

$\begin{array}{1 1}b^2=a^2(1-e^2)\\a^2=b^2(1-e^2)\\a^2=b^2(e^2-1)\\b^2=a^2(e^2-1)\end{array} $

1 Answer

Comment
A)
Toolbox:
  • In an ellipse $\large\frac{x^2}{a^2}+\frac{y^2}{b^2}$$=1$ if $a< b$,$e$ is the eccentricity then,$a^2=b^2(1-e^2)$
Answer : $a^2=b^2(1-e^2)$
In an ellipse $\large\frac{x^2}{a^2}+\frac{y^2}{b^2}$$=1$ if $a< b$ then,$a^2=b^2(1-e^2)$
Help Clay6 to be free
Clay6 needs your help to survive. We have roughly 7 lakh students visiting us monthly. We want to keep our services free and improve with prompt help and advanced solutions by adding more teachers and infrastructure.

A small donation from you will help us reach that goal faster. Talk to your parents, teachers and school and spread the word about clay6. You can pay online or send a cheque.

Thanks for your support.
Continue
Please choose your payment mode to continue
Home Ask Homework Questions
Your payment for is successful.
Continue
Clay6 tutors use Telegram* chat app to help students with their questions and doubts.
Do you have the Telegram chat app installed?
Already installed Install now
*Telegram is a chat app like WhatsApp / Facebook Messenger / Skype.
...