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Questions  >>  CBSE XI  >>  Math  >>  Conic Sections
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Q)

The eccentricity of the hyperbola whose latus rectum is $8$ and conjugate axis is equal to half of the distance between the foci is

$\begin{array}{1 1}\large\frac{4}{3}\\\large\frac{4}{\sqrt 3}\\\large\frac{2}{\sqrt 3}\\\sqrt 5\end{array} $

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A)
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  • Length of the latus rectum of a hyperbola is $\large\frac{2a^2}{b^2}$
  • $a^2=b^2(e^2-1)$
Answer : $\sqrt 5$
The latus rectum of the hyperbola is $8$
It is given that the conjugate axis is equal to $\large\frac{1}{2}$ of the distance between the foci.
Length of the latus rectum for a hyperbola is $\large\frac{2a^2}{b^2}$$=8$
$\Rightarrow 2a^2=8b^2$
$a^2=4b^2$
$a=2b$
We know that $a^2=b^2(e^2-1)$
$4b^2=b^2(e^2-1)$
$\Rightarrow e^2=5$
$e=\sqrt 5$
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