Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Questions  >>  Olympiad-Math  >>  Class 10
Answer
Comment
Share
Q)

At a point on level ground, the angle of elevation of a vertical tower is found to be such that its tangent is $ \large\frac{5}{12}$ . On walking $192\;m$ towards the tower. the tangent of the angle of elevation is $\large\frac{3}{4}$. The height of the tower is

$\begin{array}{1 1}(A) \; 200 \\(B)\;180 \\(C)\;240 \\ (D)\;300 \end{array}$

1 Answer

Home Ask Tuition Questions
Your payment for is successful.
Continue
...