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Questions  >>  Olympiad-Math  >>  Class 10
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Q)

In a distribution, the arithmetic mean and median are respectively $30 $ and $32$ , then its mode is ________

$(A) \; 25 \\(B)\;24 \\(C)\; 22 \\(D)\; 26 $

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A)
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Solution :
Mode $= 3 median - 2 median $
given $mean =30,median =32$
mode $=3 \times 32- 2 \times 30$
$\qquad= 96-60$
mode $=36$
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