info@clay6.com
+91-9566306857
logo

Ask Questions, Get Answers

X
 
Home  >>  Olympiad-Math  >>  Class 10

In a distribution, the arithmetic mean and median are respectively $30 $ and $32$ , then its mode is ________

$(A) \; 25 \\(B)\;24 \\(C)\; 22 \\(D)\; 26 $

1 Answer

Solution :
Mode $= 3 median - 2 median $
given $mean =30,median =32$
mode $=3 \times 32- 2 \times 30$
$\qquad= 96-60$
mode $=36$
answered Nov 10, 2014 by meena.p
edited Aug 30, 2016 by meena.p
 
...