# In a distribution, the arithmetic mean and median are respectively $30$ and $32$ , then its mode is ________

$(A) \; 25 \\(B)\;24 \\(C)\; 22 \\(D)\; 26$

Solution :
Mode $= 3 median - 2 median$
given $mean =30,median =32$
mode $=3 \times 32- 2 \times 30$
$\qquad= 96-60$
mode $=36$
edited Aug 30, 2016 by meena.p