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Class 10
In a distribution, the arithmetic mean and median are respectively $30 $ and $32$ , then its mode is ________
$(A) \; 25 \\(B)\;24 \\(C)\; 22 \\(D)\; 26 $
olympiad
math
statistics
class10
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asked
Nov 10, 2014
by
meena.p
retagged
Aug 30, 2016
by
meena.p
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1 Answer
Solution :
Mode $= 3 median - 2 median $
given $mean =30,median =32$
mode $=3 \times 32- 2 \times 30$
$\qquad= 96-60$
mode $=36$
answered
Nov 10, 2014
by
meena.p
edited
Aug 30, 2016
by
meena.p
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