\[ \begin{array} ((A) 0 \quad & (B) \frac{1}{3} \quad & (C) \frac{1}{12} \quad & (D) \frac{1}{36} \end{array} \]

When a pair of die is rolled once, the sample space consists of 6 $\times$ 6 = 36 elements.

Of the possible outcomes, the only even prime number is 2, and getting a 2 on each die can occur only once.

Therefore the P (obtaining an even prime number on each die, when a pair of dice is rolled ) = $\large\frac{1}{36}$

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