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# A man on tour travels first 160 km at 64 km/hr and the next 160 km at 80 km/hr. The average speed for the first 320 km of the tour is

( A ) 71
( B ) 36
( C ) 36.33
( D ) 71.11

\begin{align*}\text{Total time taken} & = (\frac{160}{64} + \frac{160}{80})hrs \\ & =\frac{9}{2}hrs \end{align*}
\begin{align*}\therefore\text{Average speed} & = [300 \times \frac{2}{9}]km/hr \\&= 71.11km/hr\end{align*}