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Questions  >>  Olympiad-Math  >>  Class 9
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Q)

In a $\Delta ABC,AD$ is the bisector of $\angle BAC$.If $AB=6$ cm,$AC=5$ cm,and $BD=3$ cm,then $DC$=

$\begin{array}{1 1}11.3\;cm\\2.5\;cm\\3.5\;cm\\\text{None of these}\end{array} $

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A)
AB = 6cm, AC = 5cm , BD = 3cm
$\therefore$ AD is the bisector of $\angle BAC $
then ,
$\frac{AB}{AC} = \frac{BD}{DC}$
$\frac{6}{5} = \frac{3}{DC}$
6DC = 15
$DC = \frac{15}{6}$
$DC = 2.5 cm$
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