Let $E_1$ be the event that the first group wins. P($E_1$) = 0.6

Let $E_2$ be the event that the second group wins. P($E_2$) = 0.4

Let A be the event where a new product is introduced.

P (introducing a new product if the first group wins) = P (A|$E_1$) = 0.7

P (introducing a new product if the second group wins) = P (A|$E_2$) = 0.3

We need to find the probability that the new product was introduced by the second group, i.e,, P($E_2$|A).

We can use Baye's theorem, according to which $P(E_2|A) = \large\frac{P(E_2)(P(A|E_2)}{P(E_1)P(A|E_1) + P(E_2)P(A|E_2)}$

P ($E_2$|A) = $\large\frac{0.3 \times 0.4}{0.3 \times 0.4 + 0.7 \times 0.6} $ = $\large\frac{0.012}{0.012+0.042} = \frac{0.012}{0.054} = \frac{2}{9}$