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Let $f(x) = \left\{ \begin{array} {1 1} 0, & \quad x <0 \\ x^2,& \quad x \geq 0 \end{array} \right. $ Then for all x

$\begin{array}{1 1} f' \;is\;differentiable \\ f \;is\;differentiable \\ f' \;is\;continous \\all\;of\;these \end{array} $

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