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Let $0 < x > \large\frac{\pi}{4}$.Then $(\sec 2x- \tan 2x)$ equal

$\begin{array}{1 1} \tan (\pi - \large\frac{\pi}{4}) \\\tan (\large\frac{\pi}{4}-x) \\ \tan (x+ \large\frac{\pi}{4})\\\tan^2 (x+ \large\frac{\pi}{4}) \end{array} $

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