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Home  >>  CBSE XII  >>  Math  >>  Matrices
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Let $ A\;=\begin{bmatrix}2 & 4\\3 & 2\end{bmatrix}, B\;=\begin{bmatrix}1 & 3\\-2 & 5\end{bmatrix}, C\;=\begin{bmatrix}-2 & 5\\3 & 4\end{bmatrix}$ Find: $(ii) (A-B)\qquad$

$\begin{array}{1 1} \begin{bmatrix}1 & 1\\5 & 3\end{bmatrix} \\ \begin{bmatrix}1 & 1\\5 & -3\end{bmatrix} \\ \begin{bmatrix}1 & -1\\5 & -3\end{bmatrix} \\ \begin{bmatrix}1 & 1\\0 & -3\end{bmatrix} \end{array} $

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Toolbox:
  • The difference $A-B$ of two $m$-by-$n$ matrices $A$ and $B$ is calculated entrywise: $(A - B)_{i,j} = A_{i,j} - B_{i,j}$ where 1 ≤ i ≤ m and 1 ≤ j ≤ n.
Given $A\;=\begin{bmatrix}2 & 4\\3 & 2\end{bmatrix}$ and $ B\;=\begin{bmatrix}1 & 3\\-2 & 5\end{bmatrix}$, $A - B = \begin{bmatrix}2 - 1 & 4 - 3\\3-(-2) & 2-5\end{bmatrix} = \begin{bmatrix}1 & 1\\5 & -3\end{bmatrix}.$
answered Feb 27, 2013 by balaji.thirumalai
 

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