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Q)

A straight horizontal conducting rod of length $0.45\;m$ and mass $60\;g$ is suspended by two vertical wires at its ends. A current of $5.0\;A$ is setup in the rod through the wires . What will be the total tension in the wires if the direction of current is reversal keeping the magnetic field normal to the conductor in order that the tension in the wires is zero?(Ignore the mass of wires ) $g= 9.8 \;m/s^2$

$\begin{array}{1 1} 11.76\;N \\ 1.176\;N \\ 117.6\;N \\ 0.1176\;N \end{array} $

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A)
Solution :
$T= BIl+mg$
$\quad= (0.26 \times 5 \times 0.45 )+(60 \times 10^{-3} \times 9.8)$
$\qquad= 1.176\;N$
Answer : $ 1.176\;N$
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