$\begin{array}{1 1} \text{$T=-1.80 \times 10^{-2} \hat j N-m$, along negative y- direction } \\ \text{$T=1.80 \times 10^{-2} \hat j N-m,$ along positive y- direction } \\ \text{$T=-1.80 \times 10^{-2} \hat j N-m,$ along negative z- direction } \\ \text{zero} \end{array} $