Solution :
Angular momentum of electron $(L)= \large\frac{nh}{2 \pi}$
Magnetic moment of electron $M=n \times Bohr $
$\quad= n \bigg[\large\frac{eh}{4 \pi m}\bigg]$
gyromagnetic ratio $= \large\frac{\text{magnetic moment}}{\text{angular momentum }}$
$\qquad= \large\frac{neh/4 \pi m}{hh /2 \pi}$
$\qquad= \large\frac{e}{2m}$
$\qquad= constant $
It is independent of the orbit it is in
Since e is negative , the geomagnetic ratio is negative.
Answer :Negative