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# The gyro- magnetic ratio of an electron in an H- atom , according to Bohr model is

$\begin{array}{1 1} \text{independent of which orbit it is in} \\ \text{Negative} \\ \text{positive} \\ \text{increases with the quantum number n} \end{array}$

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A)
Solution :
Angular momentum of electron $(L)= \large\frac{nh}{2 \pi}$
Magnetic moment of electron $M=n \times Bohr$
$\quad= n \bigg[\large\frac{eh}{4 \pi m}\bigg]$
gyromagnetic ratio $= \large\frac{\text{magnetic moment}}{\text{angular momentum }}$
$\qquad= \large\frac{neh/4 \pi m}{hh /2 \pi}$
$\qquad= \large\frac{e}{2m}$
$\qquad= constant$
It is independent of the orbit it is in
Since e is negative , the geomagnetic ratio is negative.