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The fraction of total volume occupied by the atoms present in a simple cube is

$\begin{array}{1 1} \frac{\pi}{3 \sqrt 2} \\ \frac{\pi}{4 \sqrt 2} \\ \frac{\pi}{4} \\ \frac{\pi}{6} \end{array} $

I have a doubt in that question please send me solution....

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Answer :$ \frac{\pi}{6} $
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