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Home  >>  CBSE XII  >>  Math  >>  Determinants
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Write Minors and Cofactors of the elements of following determinants: $ (ii) \quad \begin{vmatrix} 1&0&4 \\ 3&5&-1 \\ 0&1&2 \end{vmatrix} $

Note: This is part 2 of a 2 part question, split as 2 separate questions here.
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  • Minor of an element $a_{ij}$ of a determinant is the determinant obtained by deleting it $i^{th}$ row and $j^{th}$ column in which $a_{ij}$ lies.Minor of an element $a_{ij}$ is denoted by $M_{ij}$
  • Cofactor of an element $a_{ij}$ denoted by $A_{ij}$ is defined by $A_{ij}=(-1)^{i+j}M_{ij}$,where $M_{ij}$ is minor of $a_{ij}$
We know that minor of the element $a_{ij}$ is $M_{ij}$,Where i is the row and j is the column.
We have $M_{11}=\begin{vmatrix}5 & -1\\1 & 2\end{vmatrix}=10-(-1)=11$
$M_{12}=\begin{vmatrix}3 & -1\\0 & 2\end{vmatrix}=6-0=6$
$M_{13}=\begin{vmatrix}3 & 5\\0 & 1\end{vmatrix}=3-0=3$
$M_{21}=\begin{vmatrix}0 & 4\\1 & 2\end{vmatrix}=-4$
$M_{22}=\begin{vmatrix}1 & 4\\0 & 2\end{vmatrix}=2-0=2$
$M_{23}=\begin{vmatrix}1 & 0\\0 & 1\end{vmatrix}=1-0=1$
$M_{31}=\begin{vmatrix}0 & 4\\5 & -1\end{vmatrix}=0-20=-20$
$M_{32}=\begin{vmatrix}1 & 4\\3 & -1\end{vmatrix}=-1-12=-13$
$M_{33}=\begin{vmatrix}1 & 0\\3& 5\end{vmatrix}=5-0=5$


answered Mar 6, 2013 by sreemathi.v

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