# The area (in square units) of the region bounded by the curves $y+2x^2=0$ and $y+3x^2=1$, is equal to :

$\begin{array}{1 1} \frac{3}{5} \\ \frac{3}{4} \\ \frac{1}{3} \\ \frac{4}{3} \end{array}$

$\frac{4}{3}$