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The area (in square units) of the region bounded by the curves $y+2x^2=0$ and $y+3x^2=1$, is equal to :

$\begin{array}{1 1} \frac{3}{5} \\ \frac{3}{4} \\ \frac{1}{3} \\ \frac{4}{3} \end{array} $

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Answer :
$ \frac{4}{3}$
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