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A straight line L through the point $(3,-1)$ is inclined at an angle of $60^{\circ}$ to the line $\sqrt 3 x+y=1$ . If L also intersects the x- axis then the equation of L is :

$\begin{array}{1 1} y+ \sqrt 3 x +2 -3 \sqrt 3=0 \\ y - \sqrt 3 x +2 + 3 \sqrt 3 = 0 \\ \sqrt 3 y -x +3+2 \sqrt 3=0 \\ \sqrt 3 y+ x -3+2 \sqrt 3=0 \end{array} $

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