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Q)

Find the complement of the angle $(10 + y)^{\circ}$.

$( A ) (90 - y)^{\circ} \\ ( B ) (80 + y)^{\circ} \\ ( C ) (180 - y)^{\circ} \\ ( D ) (80 - y)^{\circ}$

• Two angles are complementary when their sum is $90^{\circ}$
If one angle is $10+y$, then the complementary angle is $90 - (10+y) = 90 - 10 - y = 80 - y$