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0
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Show that p ↔ q ≡ (p → q) ∧ (q → p)
tnstate
class12
bookproblem
ch9
sec1
exercise9-3
p168
q3
modelpaper
oct-2006
jun-2009
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asked
Nov 27, 2012
by
balaji.thirumalai
retagged
Apr 30, 2014
by
meena.p
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1 Answer
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Toolbox:
If $p$ and $q$ are two simple statements $p\wedge$ is the conjunction of $p$ and $q$ and $p \vee q$ is the disjunction .Negation of a statement $p$ is denoted by $\sim p$
Rules for conjunction :
$A_1$: The statement $p\wedge q$ has the truth table value $T$ whenever both $p$ and $q$ have the truth value $T$
$A_2$: The statement $p\wedge q$ has the truth value $F$ whenever either $p$ or $q$ or both have the truth value $F$
Conditional statement :"If $p$ then $q$" is written as $p\rightarrow q$ (p implies q).$p\rightarrow q$ is false only if $p$ is true and $q$ is false.If $p$ is false,then $p\rightarrow q$ is true ,regardless of the truth value of $q$
Bi-conditional statement : If $p$ and $q$ are two statements then the compound statement $p\rightarrow q$ and $q\rightarrow p$ is a bi-conditional statement,written as $p \leftrightarrow q$ (p if and only of q).$p\rightarrow q$ has the truth value $T$ whenever $p$ and $q$ have the same truth values,otherwise it is $F$
http://clay6.com/mpaimg/9.3_q3.jpg
The last two columns of the truth table are identical.
$\therefore p\rightarrow \equiv (p\rightarrow q\wedge (q\rightarrow p)$
answered
Sep 13, 2013
by
sreemathi.v
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