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Show that $\sim(p\wedge q) \equiv (\sim p)\vee (\sim q)$

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Toolbox:
  • If $p$ and $q$ are two simple statements $p\wedge$ is the conjunction of $p$ and $q$ and $p \vee q$ is the disjunction .Negation of a statement $p$ is denoted by $\sim p$
  • Rules for conjunction :
  • $A_1$: The statement $p\wedge q$ has the truth table value $T$ whenever both $p$ and $q$ have the truth value $T$
  • $A_2$: The statement $p\wedge q$ has the truth value $F$ whenever either $p$ or $q$ or both have the truth value $F$
  • Rules for disjunction :
  • $A_3$: The statement $p\vee q$ has the truth value $F$ whenever both $p$ and $q$ have the truth value $F$.
  • $A_4$: The statement $p\vee q$ has the truth value $T$ whenever either $p$ or $q$ or both have the truth value $T$
The last two columns of the truth table are identical.
$\therefore \sim(p\wedge q) \equiv (\sim p)\vee (\sim q)$
answered Sep 13, 2013 by sreemathi.v
 
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