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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Gravitation
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A spherical hole is made in a solid sphere of radius R. the mass of the sphere before hollowing was M. The gravitational field at the centre of the hole due to the remaining mass is

$\begin{array}{1 1}a) GM/2R^3 \\ b) GM/2R \\ c)GM/2R^2\\ d) GM/4R^2 \end{array} $

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A)
<div class="clay6-step-odd"><div class="clay6-basic" id="pr10">The gravitational field at the centre of the hole due to the remaining mass is GM/l^2,

Here M = 2M and R = 2R

Substituting these values we get,

The gravitational field = G(2M)/4R^2 = GM/2R^2</div></div>
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