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If we have a cylinder container of radius R and height h is completely filled with a liquid . There are two horizontal L shaped pipes of small cross section 'a' are connected to the cylinder . Now if the two pipes are opened . Then torque would be applied by the liquid is ?



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<div class="clay6-step-odd"><div id="pr10" class="clay6-basic">F = rate of change of momentum = mass of the water striking per second $\times$ velocity = $(AV\rho) \times v^2$ ( $\rho$ = density of the liquid) but $v^2 = 2gh$ Hence $F = 2Av\rho gh$ Torque $T= F \times d , d= 2r$ Therefore Torque $t = 2\times2A\rho ghr = 4A\rho ghr$</div></div>
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